x^2-20x-25=-4

Solution for x^2-20x-25=-4 equation:

x^2-20x-25=-4

We move all terms to the left:

x^2-20x-25-(-4)=0

We add all the numbers together, and all the variables

x^2-20x-21=0

a = 1; b = -20; c = -21;
Δ = b2-4ac
Δ = -202-4·1·(-21)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-22}{2*1}=\frac{-2}{2}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+22}{2*1}=\frac{42}{2}
=21
$